Force between two electrons

The electrostatic force acting on electron 1 because of the charge on electron 2 is given by the Coulomb force law,

\( \large \vec{F} =\frac{e^2}{4\pi\epsilon_0 |\vec{r}_2-\vec{r}_1 |^2}\hat{r}_{2\rightarrow 1} \)  [N]

Here $e$ = 1.6022×10-19 C is the elementary charge, $\epsilon_0$ = 8.854×10-12 F/m is the permittivity constant, and $\hat{r}_{2\rightarrow 1}$ is the unit vector pointing from electron 2 towards electron 1.

Electron 1 is at position,

 [nm],

and electron 2 is at position,

 [nm].

What is the force on electron 1?

$\vec{F} = $ $\hat{x} + $ $\hat{y} + $ $\hat{z}$ [N]